Download High-Yield Exam Revision Formula Sheets & Cheat Sheets PDF (NEET, JEE, UPSC, SSC, Defense)

Official Revision MatrixPhase 2 Verified Standards

NEET UG Physics & Organic Chemistry Matrix

High-frequency kinematics, lens combinations, organic reaction pathways, and physiology deficiencies.

Kinematics & Stopping Distance Rule

High-Yield Module

Core Mathematical Formula

Stopping Distance s ∝ v² | W_net = ΔK = (1/2)m(v² - u²) | Power P = F · v

Intuitive Logic:Stopping distance is proportional to the square of your speed. If a moving object doubles its velocity, the braking distance required to bring it to a dead stop quadruples (2² = 4 times).

Easy Intuitive Example

A motorcycle traveling at 20 km/h stops in 6 meters when full brakes are applied. If the speed is doubled to 40 km/h, the new stopping distance becomes 6 × 2² = 24 meters.

Official Exam Question & Solution

An automobile traveling at velocity v comes to a complete halt in distance s under constant braking force. If the velocity is tripled to 3v, what is the new stopping distance?

Solution:Since braking distance is proportional to v², new distance s' = s × (3)² = 9s.

Answer: 9s

Optics & Thin Lens Combination

High-Yield Module

Core Mathematical Formula

Lens Formula: 1/f = 1/v - 1/u | Power P = 1 / f(in meters) | P_net = P₁ + P₂

Intuitive Logic:Lens power in Diopters (D) is simply 100 divided by the focal length in centimeters (or 1 / focal length in meters). When two thin lenses are in contact, their optical powers add algebraically.

Easy Intuitive Example

A convex lens with focal length +50 cm (+0.5 m) has Power P = 1 / 0.5 = +2.0 Diopters. Placing a -1.0 D concave lens directly against it yields a net combination power of +2.0 - 1.0 = +1.0 D.

Official Exam Question & Solution

Two thin lenses of focal lengths +20 cm and -40 cm are placed in direct physical contact. What is the equivalent optical power of the combination?

Solution:P₁ = 100 / (+20) = +5.0 D. P₂ = 100 / (-40) = -2.5 D. Combined power P_net = P₁ + P₂ = 5.0 - 2.5 = +2.5 D.

Answer: +2.5 Diopters

Aldol Condensation vs Cannizzaro Reaction

High-Yield Module

Core Mathematical Formula

Aldol: Carbonyl with α-Hydrogen + dil. NaOH | Cannizzaro: Carbonyl with ZERO α-Hydrogen + conc. NaOH

Intuitive Logic:Check the carbon adjacent to the carbonyl group (C=O). If it has at least one hydrogen, it undergoes Aldol condensation. If it lacks an α-hydrogen (such as Formaldehyde or Benzaldehyde), it undergoes self-redox (Cannizzaro).

Easy Intuitive Example

Acetaldehyde (CH₃CHO) has 3 α-hydrogens on its methyl group, so it reacts via Aldol. Formaldehyde (HCHO) has no α-carbon at all, so it reacts via Cannizzaro to produce Methanol and Sodium Formate.

Official Exam Question & Solution

Which of the following aldehydes will NOT undergo Aldol condensation: (A) Acetaldehyde, (B) Propanal, (C) Benzaldehyde, (D) Butanal?

Solution:Benzaldehyde (C₆H₅CHO) has its carbonyl group attached to a phenyl ring carbon that has no hydrogen. Lacking α-hydrogens, it undergoes Cannizzaro instead of Aldol.

Answer: (C) Benzaldehyde

Vitamins, Cofactors & Deficiency Disorders

High-Yield Module

Core Mathematical Formula

Fat-Soluble: A, D, E, K | Water-Soluble: B-Complex, C | Vit B12: Cobalt Core (Pernicious Anemia)

Intuitive Logic:Fat-soluble vitamins are stored in liver/adipose tissue; water-soluble vitamins are excreted in urine. Vitamin B12 requires Castle's intrinsic factor secreted by stomach parietal cells for intestinal absorption.

Easy Intuitive Example

If a patient undergoes surgical stomach resection (gastrectomy), intrinsic factor secretion ceases, halting Vitamin B12 absorption and triggering macrocytic pernicious anemia.

Official Exam Question & Solution

Which transition metal ion forms the essential coordination center inside Vitamin B12 (Cyanocobalamin)?

Solution:Vitamin B12 contains a central Cobalt (Co) ion coordinated inside a planar corrin macrocycle.

Answer: Cobalt (Co)

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